Question

10 ml of 0.1 M solution of metal ion is
completely reacted with 20 ml of 0.1 N.
solution in acidic medium. Calculate the
oxidation state of the metal ion.​

Answer 1

Answer:

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Answer 2

Answer: The oxidation state of metal ion is +2

Explanation:

In a chemical reaction, equivalents of the reacting substances are same. According to the law of equivalence, whenever two substances react, the equivalents of one will be equal to the equivalents of other and the equivalents of any product will also be equal to that of the reactant.

Hence, equivalents are conserved in a reaction.

Let the oxidation state of metal ion be +y.

n factor of metal = y

Molarity of metal ion solution = 0.1 M

Volume of metal ion solution = 10 ml

Equivalents of metal ion = Molarity × Volume × n-factor

Equivalents of metal ion =  0.1 × 10 × y

Equivalents of metal ion =  y

Normality of other reactant = 0.1 N

Volume of other reactant =  20 ml

Equivalents of other reactant  = Molarity × Volume × n-factor

Equivalents of other reactant  = Normality × Volume

Equivalents of other reactant  =  0.1 × 20

Equivalents of other reactant  =  2

Equivalents of reacting substances are equal.

Therefore,

⇒ y = 2

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