Question

10 ml of 0.1 N HCl =0.0084 g NaHCO3 ...how's??

Answer 1

Explanation:

As normality is about gram equivalent weight

so first find the gram equivalent weight of HCl we get 1×10-3

then the gram equivalent weight of both is same then multiply the above value with the formulla mass of NaHCO3 (84)

we get 0.0084g