10 ml of 0.1 N HCl =0.0084 g NaHCO3 ...how's??
Answers
Answered by
1
Explanation:
As normality is about gram equivalent weight
so first find the gram equivalent weight of HCl we get 1×10-3
then the gram equivalent weight of both is same then multiply the above value with the formulla mass of NaHCO3 (84)
we get 0.0084g
Similar questions
Math,
6 months ago
India Languages,
6 months ago
History,
11 months ago
Math,
11 months ago
Biology,
1 year ago