10 mL of 0.2 N HCI, 40 mL of 0.3 N HNO, and
50 mL of 0.4 N H SO, are mixed together. The
normality of the final solution will be :
Answers
Answered by
0
Answer:
Correct option is
D
0.4
We know that,
N
1
V
1
=N
3
V
Therefore,
N
3
=
300ml
0.6N×200ml
N
3
=0.4N
Hence the correct option is D.
Answered by
0
Explanation:
Resulting normality =
V
1
+V
2
+V
3
(N
1
V
1
+N
2
V
2
+N
3
V
3
)
⇒
(0.05+0.05+0.1)
(0.2×0.05)+(0.1×0.05)+(0.2×0.1)
=0.175 N
Option C is correct
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