10 ml of 0.5 N HCI, 30 ml of 0.1 N HNO; and 75 ml of 0.2 N H.SO, are mixed together
The normality of the mixture is:
(1) 0.2 N
(2) 2N
(3)0.08 N
(4)0.4 N
plz explain
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Correct question :
10 ml of 0.5 N HCI , 30 ml of 0.1 N HNO₃ and 75 ml of 0.2 N H₂SO₄ , are mixed together. The normality of the mixture is:
(1) 0.2 N
(2) 2N
(3)0.08 N
(4)0.4 N
Given :
The given solution are mixed
- 10ml 0.5N HCl
- 30ml 0.1N HNO₃
- 75 ml of 0.2 N H₂SO₄
To find :
Normality of final solution
Formula used :
N₁V₁ + N₂V₂ + N₃V₃ = N₄V₄
Solution :
As all added solution are acids, we will use above mentioned formula to find normality of mixture.
{ Note - We can take volume in ml also }
- V₁ = 10ml N₁ = 0.5N
- V₂ = 30ml N₂ = 0.1N
- V₃ = 75ml N₃ = 0.2N
V₄ = Volume of final solution = V₁ + V₂ + V₃
V₄ = 10ml + 30ml + 75ml
V₄ = 115ml
Putting above value in N₁V₁ + N₂V₂ + N₃V₃ = N₄V₄
(10×0.5) + (30×0.1) + (75×0.2) = N₄(115)
5 + 3 + 15 = N₄(115)
23 = N₄(115)
N₄ = 23 ÷ 115
N₄ = 0.2 N
ANSWER :
Option (1) 0.2N
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