Question

10 ml of 1.8 m acetic acid (ch3cooh) is titrated with 1.0 m sodium hydroxide (naoh).

Answer 1

Concept :

According to molarity equation

$(CH_{3}COOH) M_{1}V_{1} = M_{2}V_{2} (NaOH)$

Explanation:

On substituting given values of molarity and volume in above molarity equation

We get,

10×1.8 = 1×V (NaOH)

Volume of NaOH required = 10×1.8 = 18 mL

Conclusion:

Volume of NaOH = 18 mL