10 mL of 10 ^ - 5 * N Mhydroxide solution is diluted to one litre. Assuming complete ionisation, the pH of the resulting solution is
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NaOH completely ionizes as : NaOH→Na++OH−
∴[OH−]=[NaOH]=N1000=10−3N=10−3M (∵ Eq. mass = Mol. Mass in case of NaOH)
Now, as [H3O+][OH−]=10−14∴[H3O+]=10−14[OH−]=10−1410−3=10−11
∴pH=−log[H3O+]=−log10−11=11
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10 mL of 10 ^ - 5 * N Mhydroxide solution is diluted to one litre. Assuming complete ionisation, the pH of the resulting solution is
please help ASAP!!!
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