Question

10 ML of 2(M) Na OH solution is
added to 200 mL of 0.5(M) of
Na oH
solution what is the final
concentration,​

Answer 1

Explanation:

initial moles= 10×2/1000=1/50

final moles = 200×0.5/1000=1/10

total moles= 1/10+1/50=60/500=6/50

total volume =210ml

final concentration = 6×1000/50×210=60/5×21=12/21M