10 ML of 2(M) Na OH solution is
added to 200 mL of 0.5(M) of
Na oH
solution what is the final
concentration,
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Explanation:
initial moles= 10×2/1000=1/50
final moles = 200×0.5/1000=1/10
total moles= 1/10+1/50=60/500=6/50
total volume =210ml
final concentration = 6×1000/50×210=60/5×21=12/21M
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