Question

10 ml of 2(M) NaOH solution is added to 200 ml of 0.5 (M) of NaOH solution. What is the final concentration?

Answer 1

◆ 2M NaOH
•2moles of NaOH in 1l or 1000ml of solution
•So in 10ml, number of moles
= (2/1000)×10
=0.02moles

Similarly,
◆0.5M NaOH
•0.5moles of NaOH present in 1000ml of solution
• So in 200ml, number of moles
=(0.5/1000)×200=0.1moles

●
•Now the final solution has (0.1+0.02)moles = 0.12moles
•Volume of the final solution = (200+10)ml=210ml=0.21l

●Thus the final concentration
=0.12/0.21
=0.57M
=0.6 M (approx.)

HOPE IT HELPS..... :-)

Answer 2

Answer:

Molarity is the concentration of x moles of solute in 1 L of solution. ... How many moles of Co2+ are present in 0.200 L of a 0.400 M solution of CoI2? .... If 450 mL of 6.0 M KBr solution is diluted to 900 mL, what is the concentration of the KBr solution .... If I add water to 100 mL of a 0.15 M NaOH solution until the final volume

Explanation: