10 ml of 2(M) NaOH solution is added to 200 ml of 0.5 (M) of NaOH solution. What is the final concentration?
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◆ 2M NaOH
•2moles of NaOH in 1l or 1000ml of solution
•So in 10ml, number of moles
= (2/1000)×10
=0.02moles
Similarly,
◆0.5M NaOH
•0.5moles of NaOH present in 1000ml of solution
• So in 200ml, number of moles
=(0.5/1000)×200=0.1moles
●
•Now the final solution has (0.1+0.02)moles = 0.12moles
•Volume of the final solution = (200+10)ml=210ml=0.21l
●Thus the final concentration
=0.12/0.21
=0.57M
=0.6 M (approx.)
HOPE IT HELPS..... :-)
•2moles of NaOH in 1l or 1000ml of solution
•So in 10ml, number of moles
= (2/1000)×10
=0.02moles
Similarly,
◆0.5M NaOH
•0.5moles of NaOH present in 1000ml of solution
• So in 200ml, number of moles
=(0.5/1000)×200=0.1moles
●
•Now the final solution has (0.1+0.02)moles = 0.12moles
•Volume of the final solution = (200+10)ml=210ml=0.21l
●Thus the final concentration
=0.12/0.21
=0.57M
=0.6 M (approx.)
HOPE IT HELPS..... :-)
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2
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