Question

10 mL of a given hydrogen peroxide sample
(density 1.2 g/mL) is titrated with M/50
solution of KMnO4 in acidic medium. The
volume of KMnO4 solution used is found
to be 28.4 mL. Based on this information,
answer the following three questions.
Question No:1
The molarity of H2O2 in the given hydrogen
peroxide sample is​

Answer 1

Milliequivalents of H

2

O

2

= Milliequivalents of MnO

4

−

10×N

1

(H

2

O

2

)≡10×

0.56

N

MnO

4

⊝

N

1

(H

2

O

2

)=

0.56

1

x volume H

2

O

2

has normality =

5.6

x

5.6

x

=

0.56

1

⇒x=10

Answer 2

Answer:

1.4

Explanation:

2MnO4 −+6H ++SH 2O 2→2Mn 2++8H 2O+50

5H 2O 2 =2MnO 4−

​

2MnO 4−xmoles /5H 2O 2ymoles

​Molarity = volumes/moles

0.5= Volume moles of MnO 4−/volume

​Moles of MnO 4- =0.5×0.025

Moles of H 2O 2 = 25

​

×0.5×0.025

Molarity = moles/v

​Volume Strength = Molarity ×112=1.4

So, the final answer is The molarity of H2O2 in the given hydrogen

peroxide sample is​ 1.4.

#SPJ3