10 mL of a solution of NaOH found to be completely neutralised by 8 mL of given solution of HCl. If we take 20 mL of same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise it, will be : A. 4mL B. 8mL C. 12mL D. 16mL
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D.)16 mL
When 20 mL of NaOH is taken it is the double the amount of solution taken earlier. So we will require double the amount of HCl taken before to neutralize the solution which 2×8=16mL
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4ml is the correct answer
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