Question

10 ml of a solution of NaOH is found to be completely neutralized by 8ml of a given solutions of HCL. If we take 20ml of same solution of NaOH, the amount of HCL solution required to neutralize it will be

Answer 1

Explanation:

10ml NaOH is neutralised by 8ml HCl

10ml:8ml

Therefore 10*2ml=8*2ml

Therefore 16ml of HCl is required to neutralise 20ml of NaOH.

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