10 mL of a Solution of NaOH is found to be completely
neutralised by 8 mL of a given
solution of HCL. if we take 20 mL of the
same soltion of NaOH , the amount HCL
Solution (the same solution as before
Hequined to neutralise it
will be
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Explanation:
If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be. Solution : 10 mL of NaOH will require HCl = 8 mL and 20 mL of NaOH will require HCl= 16 mL. Therefore, (d) is the correct
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