*10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralize it will be:*
1️⃣ 4 mL
2️⃣ 8 mL
3️⃣ 12 mL
4️⃣ 16 mL
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MARK S BRILLIAT
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Step-by-step explanation:
■16 mL
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