Question

10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HC1. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be
(a) 4 mL
(b) 8 mL
(c) 12 mL
(d) 16 mL

Answer 1

Answer:

16 ml of HCL requires to neutralize, 20 ml of NaOH

Explanation:

10 ml of NaOH requires to neutralize 8 ml of HCL

If, 20 ml of NaOH requires to neutralize = ? amount of HCL

10 ml of NaOH  = 8 ml oh HCL equation 1

20 ml of NaOH = x equation 2

Cross multiply equation (1) and (2)

10 x  = 20 8

x = 160/10

x = 16 ml

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Answer 2

Since 10 ml of NaOH requires 8 mL of HCL, 20 ml of NaOH require 8 x 2 = 16mL of HCl. Hence, the answer is:-

(d) $\huge\mathrm\green{16\:ml}$