Question

10 ml of a solution of sodium hydroxide is found to be completely neutralized by 8 ml of given solution of hydrochloric acid. If we take 20 ml of the same solution of sodium hydroxide then the amount of hydrochloric acid required to neutralize it will be? Calculate.

Answer 1

$\huge\bf{\pink{\mid{\overline{\underline{Answer: 16 ml\:of\:HCl(aq)}}}\mid}}$

$\huge\bf{\green{\mid{\overline{\underline{Solution:}}}\mid}}$

The amount of HCl required to neutralise 10 ml of NaOH = 8 ml.

Therefore, the amount of HCl required to neutralise 20 ml of NaOH

The amount of HCl = 8/10 × 20

The amount of HCl = 16 ml

$\huge\bf{\blue{\mid{\overline{\underline{HCl(aq) = 16 ml}}}\mid}}$

Answer 2

Concept :

We have to use Unitary Method in above question for solution.

Solution :

We know that, Sodium Hydroxide = NaOH and Hydrochloric Acid = HCl ; then

→ 10 ml of NaOH is needed to completly neutralize = 8 ml of HCl.

→ 1 ml of NaOH is needed to neutralize = 8/10 ml of HCl

→ Then, 20 ml of NaOH can neutralize = 8/10 × 20 ml of HCl

∴ 20 ml of NaOH can neutralize = 16 ml of HCl

Hence 16 ml of HCl can be neutralized by 20 ml of NaOH.

Answer : 16 ml of HCl