Question

10 ml of gaseous hydrocarbon on combustion gives 40 ml of co2 and 50 ml of h2o. the hydrocarbon is:
c4h5
c8h10
c4h8
c4h10
pls... explain it also.

Answer 1

this question is from mole concept and in mole we study a law named Ideal gas law by avagadro.A/c to which all the gases occupies same volume under similar conditions of tempurature and pressure so the no of moles is going be equal
we can take them as in ratio
10 : 40: 50
    or 
1:4:5
and as there in no carbon in h2o that means all the carbon has added to co2 from hydrocarbon
so we can write that 
10ml of hydrocarbon produces 40ml of co2
or in ratio as 10:40 or 1:4
and the hydrogens have benn added to h20
so 10ml of hydrocarbon produces 50ml of h2o
or in ratio as 10:50or 1:5
and if there are 5 [h2o] that means 10hydrogens
so 1 mole of hydrocarbon has 10 moles of hydrogen 
so that there are 4 carbons and 10 hydrogen 
 C4H10

Answer 2

Answer:

Explanation:this question is from mole concept and in mole we study a law named Ideal gas law by avagadro.A/c to which all the gases occupies same volume under similar conditions of tempurature and pressure so the no of moles is going be equal

we can take them as in ratio

10 : 40: 50

    or 

1:4:5

and as there in no carbon in h2o that means all the carbon has added to co2 from hydrocarbon

so we can write that 

10ml of hydrocarbon produces 40ml of co2

or in ratio as 10:40 or 1:4

and the hydrogens have benn added to h20

so 10ml of hydrocarbon produces 50ml of h2o

or in ratio as 10:50or 1:5

and if there are 5 [h2o] that means 10hydrogens

so 1 mole of hydrocarbon has 10 moles of hydrogen 

so that there are 4 carbons and 10 hydrogen