Chemistry, asked by kennu, 1 year ago

10 ml of gaseous hydrocarbon on combustion gives 40 ml of co2 and 50 ml of h2o. the hydrocarbon is?

Akash0501: what do you mean by hydrocarbon is?

Answers

Answered by ork

220

Provided they are all gases then the formula is going to be
C4H10

they key here is that 1 mole of any ideal gass occupies the same volume as 1 mole of any other ideal gas under the same conditions of temperature and pressure. So, since the same volume of any ideal gas has the same number of moles then you can treat the ratio of volumes as the ratio of moles.

the ratio of volumes is
10 : 40 : 50
1 : 4 : 5

all the Carbon from the hydrocarbon is in the CO2
10 ml of hydrocarbon produces 40 ml CO2,
1 : 4 ratio
So 1 mole hydrocarbon has 4 moles Carbon

All the H ends up in the water
10 ml hydrocarbon produces 50 ml water,
1 : 5 ratio,
but also each water has 2 H atoms
So 1 mole hydrocarbon has 10 moles Hydrogen

which gives
C4H10

Answered by aditypatil71

first solution -

10 mL of gaseous hydrocarbon on combustion gives 40 mL of CO2

The number of C atoms in the formula unit is 40/10×1=4

and

10 mL of gaseous hydrocarbon on combustion gives 50 mL of H2O

50/10×2 =10

The hydrocarbon is C4H10

Second solution is:-

the ratio of volumes is

10 : 40 : 50

1 : 4 : 5

all the Carbon from the hydrocarbon is in the CO2

10 ml of hydrocarbon produces 40 ml CO2,

1 : 4 ratio

So 1 mole hydrocarbon has 4 moles Carbon

All the H ends up in the water

10 ml hydrocarbon produces 50 ml water,

1 : 5 ratio,

but also each water has 2 H atoms

So 1 mole hydrocarbon has 10 moles Hydrogen

which gives

C4H10

You can balance an equation for combustion of C4H10 to check the answer

C4H10 + 13/2 O2 --> 4CO2 + 5H2O