Question

) 10 ml of H₂O₂ solution reacts with KI solution to produce 0.5 gm of iodine. Calculate % purity of H₂O2. H₂O₂ + 2KI = 2 Koh I2​

Answer 1

Explanation:

Write the balanced eqn. first,

H2O2 + 2 KI ------------------> I2 + K2O + H2O

moles of I2 = 0.5/254 = 0.00196

from mole analysis,

moles of H2O2 would be: 0.00196

mass of H2O2 = 0.00196*34 = 0.066929 gm.

% purity = 0.066929/10 * 100 = 0.66929 %