Chemistry, asked by sowmy635, 1 year ago

10 mL of HCl and 10 mL of NaOH solutions are contained in two separate
beakers labeled I and II respectively.
On adding zinc granules to both, it is observed that at room temperature :
(a) gas is evolved in beaker II but not in beaker I
(b) no gas is evolved in either of the two beakers
(c) gas is evolved vigorously in both
(d) gas is evolved vigorously in beaker I but not so in beaker II.

Answers

Answered by Anonymous
53
Hope it helps.....!!!
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The correct option is (d)

=>Gas is evolved vigorously in the beaker 1 with HCL and not in beaker 2 with NaOH. This is because zinc reacts very fast with the HCL and very slowly with the NaOH at room temperature.
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#Be Brainly✌️
Answered by AnkitaSahni
1

The observation will be gas is evolved vigorously in beaker I but not so in beaker II. (option d)

The Reaction of HCl and Zn

  • The reaction of an acid and metal leads to the formation of salt and the evolution of Hydrogen gas.
  • The reaction is written as:

                    Zn(s) + HCl(aq)    →     ZnCl₂(aq) + H₂ (g)

  • In this reaction, hydrogen gas is bubbled out fast as the reaction proceeds vigorously.

The reaction of NaOH and Zn

  • The reaction of a base and metal leads to the formation of salt and the evolution of hydrogen gas.
  • The reaction is written as:

                    2NaOH(aq) + Zn(s)     →  Na₂ZnO₂(aq)    + H₂(g)

                                                           sodium zincate

This reaction is not as vigorous as the reaction of Zn and HCl.  

Thus, the correct option is (d) gas is evolved vigorously in beaker I but not so in beaker II.

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