10 mL of HCl and 10 mL of NaOH solutions are contained in two separate
beakers labeled I and II respectively.
On adding zinc granules to both, it is observed that at room temperature :
(a) gas is evolved in beaker II but not in beaker I
(b) no gas is evolved in either of the two beakers
(c) gas is evolved vigorously in both
(d) gas is evolved vigorously in beaker I but not so in beaker II.
Answers
Answered by
53
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The correct option is (d)
=>Gas is evolved vigorously in the beaker 1 with HCL and not in beaker 2 with NaOH. This is because zinc reacts very fast with the HCL and very slowly with the NaOH at room temperature.
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_______________
The correct option is (d)
=>Gas is evolved vigorously in the beaker 1 with HCL and not in beaker 2 with NaOH. This is because zinc reacts very fast with the HCL and very slowly with the NaOH at room temperature.
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Answered by
1
The observation will be gas is evolved vigorously in beaker I but not so in beaker II. (option d)
The Reaction of HCl and Zn
- The reaction of an acid and metal leads to the formation of salt and the evolution of Hydrogen gas.
- The reaction is written as:
Zn(s) + HCl(aq) → ZnCl₂(aq) + H₂ (g)
- In this reaction, hydrogen gas is bubbled out fast as the reaction proceeds vigorously.
The reaction of NaOH and Zn
- The reaction of a base and metal leads to the formation of salt and the evolution of hydrogen gas.
- The reaction is written as:
2NaOH(aq) + Zn(s) → Na₂ZnO₂(aq) + H₂(g)
sodium zincate
This reaction is not as vigorous as the reaction of Zn and HCl.
Thus, the correct option is (d) gas is evolved vigorously in beaker I but not so in beaker II.
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