10 ml of liquid carbon disulphide (sp. Gravity 2.63) is burnt in oxygen.Find the volume of the resulting gases measured at STP
Answers
Answered by
12
Reaction of CS2 with O2
=> CS2 + xO2 = CO2 + 2SO2
Molecular weight of CS2 = 12 + 32*2 = 76
Mass of CS2 = Specific gravity * Volume = 2.63 * 10 =26.3 grams
Moles of CS2 = 26.3/76 = 0.346moles
•.• 1 mole of CS2 generate 3 moles of gases
.•. 0.346 moles of CS2 generate = 3*0.346 = 1.038
•.• volume occupied by 1 mole at stp = 22.4 liters
So volume occupied by 1.038 mole at stp = 22.4*1.038 = 23.254 liters
Hence, Volume occupied by gas produced is equal to 23.254 liters
=> CS2 + xO2 = CO2 + 2SO2
Molecular weight of CS2 = 12 + 32*2 = 76
Mass of CS2 = Specific gravity * Volume = 2.63 * 10 =26.3 grams
Moles of CS2 = 26.3/76 = 0.346moles
•.• 1 mole of CS2 generate 3 moles of gases
.•. 0.346 moles of CS2 generate = 3*0.346 = 1.038
•.• volume occupied by 1 mole at stp = 22.4 liters
So volume occupied by 1.038 mole at stp = 22.4*1.038 = 23.254 liters
Hence, Volume occupied by gas produced is equal to 23.254 liters
Similar questions