10 ml of NaHC2O4 is neutralized fully by 10 ml of 0.1 M of NaOH. 10ml of the same NaHC2O4 is oxidised by 10 ml of KMnO4 in an acidic medium. What is the molarity of KMnO4?
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Answer:
Hello dear,,
Explanation:
- you have to consider two processes including neutralization and redox.When NaHC2O4 is treated with NaOH , It will get neutralize and when with KMnO4 redox will takes place .
- Firstly Neutralization
- N1V1=N2V2
- 10*0.1=10*Concentration/Normality of NaHC2O4
- .Normality comes up as 0.1 which is same as molaaity as X factor is 1/
- Now In second case , Redox takes place.
- By principle of Redox
- No of equivalets of Oxidaant=No of equvalents of Reducatnt
- (Hint: X factor of KMnO4 in acidic medium is 5 AND X factor of NaHC2O4 is 1)
- thus
- 5*Molarity of KMnO4=0.1*1
- Molaity of KMno4=0.02
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