Chemistry, asked by hyndavi3007, 2 months ago

10 ml of oxygen is subjected to silent electric discharge. The final volume is 8 ml. Mole fraction of ozone in the mixture is​

Answers

Answered by Ashii24
1

Answer:

87 mL and 81 mL

Explanation:

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Answered by adventureisland
1

Given:

10 ml of oxygen is subjected to silent electric discharge

To find:

The mole fraction of ozone in mixture.

Explanation:

The initial volume of O_{2}=10ml

%of O_{2}=90%volume of O_{2} converted =90%10ml

=\frac{90}{100}*10

=0.9*10\\=9mlvolume of O_{2} unit=(10-9)ml\\=1ml

3O_{2}2O_{3}

3v2v

v\frac{2v}{3}

9ml\frac{2}{3}*9ml

6mlV_O_{2} +V_O_{3}=(1+6)ml=7ml

=(7-6)ml=1ml

The 7ml and 1ml.

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