10 ml of solution of An a is found to be completely neutralized by 8 mm of a given solution of 8 cm if we take 20 ml of the same solution of n a o h the amount of HCL solution the same solution as before required to neutralize it will be option is 4 ml number 28 ml number to 16 ml number for 12 ml
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As given :
8 mL of HCl solution is required to neutralise 10 mL of NaOH.
So as usual to neutralise 20 mL of same solution i.e. of NaOH we would need 16 mL of same solution of HCl.
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