Question

10. Mole(s) of CO2 gas obtained at STP, when 32g CH4 reacted with 32 g of oxygen is [NCERT Pg. 20] (1) 0.5 (2) 1 (3) 2 (4) 3
answer,0.5​

Answer 1

Explanation:

According to the balanced chemical equation, 64 g of oxygen can burn 16 g of methane to produce 44 g of carbon dioxide. So, 32 g of oxygen can burn only 8 g of methane (out of 32 g of methane) to produce 22 g of carbon dioxide. Now 22 g of carbon dioxide = ---- mole . no of mole = given mass / molar mass = 22g / 44g = 0.5 mole.( ans)

Answer 2

No.of moles = 0.5

The balanced equation for this chemical reaction is

CH₄ + 2O₂ --> CO₂ + 2 H₂O

From this, 16g of CH₄ combine with 64g of O₂ to give 44g of CO₂.

We are given 32g of Oxygen.It can fuse with only 8g of CH₄.

Then this reaction will give 22g of Carbon dioxide.

no.of moles = mass/molar mass

n = 22g/44g

= 0.5 moles

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