Question

10 moles of an ideal gas expands into vacuum. The work done is

Answer 1

work done in vacuum is zero

Answer 2

The work done is 0 Joules

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

$W=-P\Delta V=-P(V_2-V_1)$

W = amount of work done = ?

P = pressure = 0 atm   ( as expansion is against vacuum)

$V_1$ = initial volume

$V_2$ = final volume

Putting values in above equation, we get:

$W=-0\times (V_2-V_1)$

$W=0Joules$

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