10 moles of Mohr's salt and Fe2(SO4)3 mixture requires one litre of 1M K2Cr2O7 for complete oxidation.The number of mole Mohr's salt in mixture are
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Answer:
Cr
2
O
7
2−
+6Fe
2+
+14H
+
→2Cr
3+
+6Fe3++7H
2
O
(n=1) (Mohr's salt)
Equivalent of Fe
2+
= moles of Mohr's salt
= equivalent of K
2
Cr
2
O
7
= 500×10
−3
×6×1=3.0
Hence. mole percent of Mohr's salt
=
4
3
×100=75
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