Chemistry, asked by gurnamjattu, 6 months ago


੧. ਇੱਕ ਵਸਤੂ ਦਾ ਹਵਾ ਵਿੱਚ ਭਾਰ 10 N ਹੈ | ਪਾਣੀ
ਵਿਚ ਡੁਬੋਏ ਜਾਣ ਤੋਂ ਬਾਅਦ ਇਸ ਦਾ ਭਾਰ 8 Nਰਹਿ
ਜਾਂਦਾ ਹੈ । ਇਸ ਦੁਆਰਾ ਵਿਸਥਾਪਿਤ ਕੀਤੇ ਪਾਣੀ ਦਾ
ਭਾਰ ਹੋਵੇਗਾ। An object weighs 1ON in air
When immersed in water, it weighs
only 8 N. The weight of the liquid
displaced by the object will be: 591 #
ਰਿਚੀ ਕਹੁ ਨਾ ਹਰ 10 N ਫੈ। ਧਾਰੀ ਨੇਂ ਕੇ ਦਵਜੇ
के बाद इसका वजन 8 N रहता है। यह इसके
द्वारा विस्थापित पानी का वजन होगा।
08 N
O 10 N
12 N
O 2 N​

Answers

Answered by amitnrw
1

Given : An object weighs 10N in air . When immersed in water , it weighs only 8 N.

To Find : The weight of the liquid displaced by the object will be:

Solution:

When an object is fully immersed in water

The object suffers an apparent weight loss equal to the weight of the fluid displaced.

apparent weight of the object = Weight of object - apparent weight loss

=> apparent weight of the object = Weight of object -  weight of the fluid displaced.

Weight of object = Weight in Air = 10N

Weight in water =  apparent weight of the object  = 8N

=> 8  = 10 - weight of the fluid

=> weight of the fluid  = 2N

The weight of the liquid displaced by the object will be 2N

विस्थापित पानी का वजन 2N होगा

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