Question

10. Number of moles of Mno, required to oxidize one mole of
ferrous oxalate compeletly in acidic medium will be -
[AIPMT-2008]
(1) 7.5 moles
(2) 0.2 moles
(3) 0.6 moles
(4) 0.4 moles
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Answer 1

10FeC2O4 + 6KMnO4 + 24H2SO4 ----> 3K2SO4+ 6MnSO4 + 5Fe2(SO4)3 + 24H2O + 20CO2 So we see that 6 moles of KMnO4 is required to oxidize 10 moles of FeC2O4 Then, 1 mole of FeC2O4 would be oxidized by = 6/10=0.6