Question

10 numerical problem for pressure class 8 cbse​

Answer 1

Answer:

[ solution]

solution: Force or thrust here =F= 4 N. Area A = 0.003 m^2. Pressure exerted = P = F/A = 4/0.003 Pa = 1333.33 Pa.

solution: Force or thrust here =F=600 N. Area A = 0.012 m^2. Pressure exerted = P = F/A = 600/0.012 Pa = 5 x 10^4 Pa.

solution: Force or thrust here =F=250 N. Pressure exerted = P = 25,000 Pa.

Explanation:

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Answer 2

Answer:

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