10%of cow of a villager died in 2011. 25/2% of the remaining cows died in 2012 .if the left out cows are 63,how many cows did the villager have originally?
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Answer:
Let the number of cows be n
10% of cows died in 2011
=10% of n =n/10
cows left=n-n/10
=9n/10
25/2% of remaining died in 2012
=25/200 x 9n/10
=9n/80
Cows left =9n/10-9n/80
=72n-9n/80
=63n/80
It is given that 63 cows were left,
then, 63n/80=63
n=80
hence, number of cows villagers have originally=80
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