10% of the voters did not cast their vote in an election between two candidates. 10% of the votes polled were found invalid. The successful candidate got 54% of the valid votes and won by a majority of 1620 votes. The number of voters enrolled on the voters list was :
Answers
Step-by-step explanation:
Given:
10% of the voters did not cast their vote in an election between two candidates. 10% of the votes polled were found invalid. The successful candidate got 54% of the valid votes and won by a majority of 1620 votes.
To Find:-
The number of voters enrolled on the voters list was
Solution:-
No. of voters cast their vote=90% of x
No. of votes polled valid=90% of (90% of x)
It is given that the winner won by the majority of 1620 votes. So, 8% of the votes enrolled (valid votes) is 1620 .So,
[Number of votes enrolled is 25000]
ACQ,
Given :-
- No of voters who didn't cast vote = 10%
- No of invalid voters in election = 10%
- The successful candidate got vote = 54%
- The successful candidate won by = 1620 V
To Find :-
- The no of voters enroll in voters list = ?
Solution :-
To calculate the no of voters who voted in the election at first we have to set up equation as per the given clue in the question. The clues are 10% of the voters did not cast their vote in an election between two candidates. 10% of the votes polled were found invalid. The successful candidate got 54% of the valid votes and won by a majority of 1620 votes. Let assume the total number of votes who voted in the election be x .
Calculation begins :-
⇒ No of valid votes = 100 - 20 = 80%
⇒ No of total votes = x * 80/100 = 80x/100
⇒ winners candidate got votes = 54% of 80x/100
⇒ Losser candidate got votes = 100 - 54 = 46%
Let's set up equation here :-
⇒ Winner votes - Losser votes = 1620
⇒ 54/100 * 80x/100 - 46/100 * 80x/100 = 1620
⇒ 54 * 4x/5 * 100 - 46 * 4x/5 * 100 = 1620
⇒ 216x/500 - 176x/500 = 1620
⇒ 216x - 176x/500 = 1620
⇒ 40x = 1620 × 500
⇒ 4x = 1620 × 50
⇒ 4x = 81000
⇒ x = 20250
Hence,
⇒ Total votes were pulled in election = 20250