10% of x° is the complement of 40% of 2x° find x
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Answered by
33
10% of x= x*10/100= x/10
⇒ 40% of 2x= 2x*40/100= 4x/5
threfore,x/10+4x/5=90
⇒x+8x/10=90
⇒9x/10=90
⇒x=100
⇒ 40% of 2x= 2x*40/100= 4x/5
threfore,x/10+4x/5=90
⇒x+8x/10=90
⇒9x/10=90
⇒x=100
Answered by
32
10% of x° = 90 - 40% of 2x°
(10/100)×x° =90 - (40/100) × 2x°
x°/10= 90- 8x°/10
x°/10+8x°/10=90°
9x°/10 =90°
9x°= 90×10
x= (90×10)/9
x= 100°
(10/100)×x° =90 - (40/100) × 2x°
x°/10= 90- 8x°/10
x°/10+8x°/10=90°
9x°/10 =90°
9x°= 90×10
x= (90×10)/9
x= 100°
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