10 ohm and a 15 ohm resistor are connected in parallel in a cricut with 12V battery
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Resistor 1= R1= 10ohm
Resistor 2= R2=15ohm
Potential Difference= 12v
A) Minimum Current flowing through the circuit
when the two resistors are connected in series
Rs= R1+R2
Rs= 10+15
Rs= 25ohm
Current (I)= V/Rs
=12/25
=0.48A
B) Maximum current flows through the circuit when it is connected in parallel
Rp= R1×R2/R1+R2
Rp= 150/25
Rp= 6ohm
Current (I)=V/Rp
=12/6
=2A
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