Question

10 ohms and 20 ohms resistors are combined in series. Calculate the current flowing when the combination is connected to 6 volts battery . Also find the potential difference across 10 ohms and 20 ohms resistors separately?

Answer 1

Answer:

(1) Current flowing when connected together

$R_{1}$=10Ω

$R_{2}$=20Ω

V=6 V

$R_{s}$=$R_{1}$+$R_{2}$=10+20=30Ω

I=$\frac{V}{I}$=$\frac{6}{30}$=0.2Ω

(2)Current flowing through resistors separately

Since the resistors are in series, the current flowing through them is equal

a. $R_{1}$=10Ω

I=0.2Ω

V=IR=0.2×10=2 V

b.$R_{2}$=20Ω

V=IR=0.2×20=4 V