Question

10. On taking Laplace transform of differential equation
dt"
+ 4y(t) = sin t, with
y(0) = 0, y'(0) = 0, the subsidiary equation is (s? + 4) Y(s) =
Y(S)=+1)
The solution of
differential equation is
(2)
(A) y(t):
1/3
sin t
his
sin 2t
(B) y(t) =
yt) = ; (cost-Źcos 21
(D) y(t) = 1 (sin t + sin 26)
1
(C) y(t) = ž (cos t + cos 2t)
d'y
dy
-21 with​

Answer 1

On taking Laplace transform of differential equation

dt"

+ 4y(t) = sin t, with

=y(0) = 0, y'(0) = 0, the subsidiary equation is (0+ 4) Y(s) =

Y(S)=+1)

So,The solution of

differential equation is4y(t)=0+4+1

(2)

(A) y(t):

1/3

sin t

his

sin 2t

(B) y(t) =

yt) = ; (cost-Źcos 21

(D) y(t) = 1 (sin t + sin 26)

1

(C) y(t) = ž (cos t + cos 2t)

d'y

dy

-21 with