Question

10. One of the angles of a triangle is 80% and the other two angles are equal Find the measure of
each of the equal angles​

Answer 1

Answer:

50⁰.

Step-by-step explanation:

Since they are equal we assume both of them to be x. So according to angle sum property of triangle, the sum of all the interior angles of a triangle sum up to 180°. Hence the angle measure of the two equal angles are 50°.

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Answer 2

Step-by-step explanation:

Given:

Angle of a triangle=80°=m(BAC)

Two Angles of Triangle=m(ABC)=m(ACB)

To find:

Measures of each equal angle

Solution:

m(BAC)+m(ABC)+m(ACB)=180°....(Sum of angles of a triangle.)

80°+m(ABC)+m(ACB)=180°....(GIVEN)

2 m(ABC)=180°-80°

2 m(ABC)=100°

m(ABC)=100°/2

m(ABC)=50°

m(ABC)=m(ACB)....(GIVEN)

THEREFORE, m(ACB)=50°

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