Question

10 pipes required to fill a tank 60 minutes . how long will it take is 5 pipes are there​

Answer 1

Given: $10$pipes required to fill a tank in $60$minutes.

We have to find the time required to fill $5$pipes.

We are solving in the following way:

Let the desired time to fill the tank be $x$minutes.

We have,

$10$pipes required to fill a tank in $60$minutes.

As we know that the lesser the number of pipes, the more will be the time required by it to fill the tank.  

So, this is a case of inverse proportion.

$\therefore 60\times10=x\times 5\\=>600=5x\\\\=>x=\frac{600}{5} \\\\=>x=120$

Hence, the time is taken to fill the tank by$5$ pipes will be$120$ minutes or $1$hours.

Answer 2

Answer:

Time required to fill a tank by using 5 pipes is 12 minutes.

Step-by-step explanation:

To find-

Time required to fill a tank by using 5 pipes

Solution-

Here work done means fill the tank .

Workers means pipe and time in a minutes

∴ Work done = Workers × Time

10 pipes required to fill a tank 60 minutes. (Given)

we can write it as,

work done = $10$×$60$       (1)

Then we have to find a time required to fill tank let it is $x$

we can write second equation as ,

work done = $5$× $x$    (2)

As both equation as work done

By equating equation (1) and (2)

$10$ × $60$ = $5$ × $x$

$60 = 5x\\\frac{60}{5} = x\\12=x$

So, Time required to fill a tank by using 5 pipes is 12 minutes.