Question

10. PO is a tangent drawn from a point Po
circle with centre andooris a diameter
of the circle such that POR - 120°. then
find _OPO​

Answer 1

Answer:

30°

Step-by-step explanation:

∠QOP + ∠POR = 180°

∠QOP + 120° = 180°

∠QOP = 180° - 120°

∠QOP = 60°

In ΔPOQ

∠QOP + ∠OPQ + ∠PQO = 180°

60° + ∠OPQ + 90°

= 180° 150° + ∠OPQ

= 180° ∠OPQ

= 180° - 150°

∠OPQ = 30°