Math, asked by lavnish123, 1 year ago

10 points
==========
will mark as brainliest
===========
please help.

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Answered by Gautam22121998

5

2sinAcosA+(cosA+sinA)²-(2cosA+sinA)²=psin²A+q
L.H.S=2sinAcosA+cos²A+sin²A+2sinAcosA-[4cos²A+sin²A+4sinAcosA]
=1+4sinAcosA-[3cos²A+1+4sinAcosA]
=1+4sinAcosA-[3(1-sin²A)+1+4sinAcosA]
=1+4sinAcosA-[3-3sin²A+1+4sinAcosA]
=1+4sinAcosA-[4-3sin²A+4sinAcosA]
=1+4sinAcosA-4+3sin²A-4sinAcosA
=3sin²A-3
now equating it with psin²A +q
therefore,
p=3 &
q=(-3)

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