Question

10 Prove that
(1) 2(cos squre 45° +tan squre 60°)
- 6 (sinsqure45° - tansquare
30°) = 6
(in
OY
4​

Answer 1

Answer:

we need proof

Step-by-step explanation:

• [2(cos 45°)^2 + (tan 60°)^2]-6[ (sin 45)^2 -tan 30] =6
• cos 45 °= 1/√2
• tan 60°=√3
• sin 45°= 1/√2
• tan 30°= 1/√2
• u can do by using this