Question

10. Prove that AABD ACBD. Find the values
of x and y, if ZABD = 35°, ZCBD - (3x+5)",
ZADB = (y - 3), ZCDB = 25°
35°
B
25°
(3x+5)
Triangles
81​

Answer 1

Answer:

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Step-by-step explanation:

Given : In the figure AB = BC, AD = DC

∠ABD = 50, ∠ADB = y - 7°

∠CBD = x + 5°, ∠CDB = 38°

To find: The value of x and y

In △ABD and △CBD

BD = BD (common)

AB = BC (given)

AD = CD (given)

∴ △ABD ≅ △CBD (SSS axiom)

∴ ∠ABD = ∠CBD

=> 50 = x + 5° => x = 50° - 5 = 45°

and ∠ADB = ∠CDB

⇒ y - 7° = 38° ⇒ y = 38° + 7° = 45°

Hence x = 45°, y = 45°