Question

10. Prove that the sum of the exterior angles of a triangle taken inn order is
360°, i.e., x + y + z = 360°.
[Hint: Let int. 2A = aº, int. ZB = bº, int. ZC = cº a
By ext. ZProperty x = a + b, y = b + c, z = a + c
x + y +z = a + b + b + c + a + c = 2(a + b + c).​

Answer 1

Answer:

Step-by-step explanation: