Question

у А
10. Prove that the sum of the exterior angles of a triangle taken in order is
360°, i.e., x + y + z = 360°
(Hint: Let int. ZA = aº, int. ZB = bº, int. C=
ca+ b + c = 180°
By ext. ZProperty x= a + b, y= b + c, z = a + c
x + y +z = a + b + b + c + a + c = 2(a + b + c).
B
Z
C
Fig. Q. 10
208​

Answer 1

Angles = 3(180 - x)

= 540° - 3x

Putting inside values-

= 540° - 180°

= 360°