Question

10.Rachel has 24 red candies and Maya has 18 green candies. They want to arrange
the candies in such a way that each row contains an equal number of candies and
also each row should have only red candies or green candies. What is the greatest
number of candies that can be arranged in each row?
11. Verify the relationship “Product of the two given numbers = HCF AND LCM”
for the numbers 96 and 132.​

Answer 1

Answer:

10)2 rows each row should contain 6 red candies

And for maya she has to arrange 2 rows each row should contain 9 green candies

Step-by-step explanation:

So,the greatest number of candies that can be arranged in each row is 9 that is the greatest number by which we compare to 6

Answer 2

Given: .Rachel has 24 red candies and Maya has 18 green candies.

To find: the greatest  number of candies that can be arranged in each row.

Solution:

Know that, The restrictions that we have are:

Each row has the same number of candies.

Each row has only one color of candy.

 To arrange the green and red candies in rows of equal numbers find the the largest common factor between 18 and 24.

$\[\begin{array}{l}18 = 2 \times 3 \times 3\\24 = 2 \times 2 \times 2 \times 3\\ \Rightarrow HCF\left( {18,24} \right) = 2 \times 3\\ \Rightarrow HCF\left( {18,24} \right) = 6\end{array}\]$

 Therefore, 6 is a common factor of 18 and 24.

Understand that each row will have 6 candy  and there will be:

$\[\frac{{18}}{6} = 3\]$ rows of green candy.

$\[\frac{{24}}{6} = 4\]$ rows of red candy.