10 raise to power x= 64 what is the value of 10 raise to power x/2 +1
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Answered by
9
10^x = 64
take log both sides
log10^x = log64
x = log64 ----(1)
now ,
10^(x/2 + 1) = P ( let )
take log both sides
log10^(x/2 + 1) = logP
(x/2 + 1) = P
put x = log64 from eqn (1)
( log64 )/2 + 1 = logP
log(64)½ +1 = logP
log8 + log10 = logP
logP = log8 × 10 = log80
P = 80
hence, 10^(x/2 +1) = 80 ( answer )
2nd method ///
=================
10^x = 64
take square root both sides
(10^x)½ = (64)½
10^x/2 = 8
multiply both sides with 10
10.10^x/2 = 8× 10
10^(x/2 + 1) =80
take log both sides
log10^x = log64
x = log64 ----(1)
now ,
10^(x/2 + 1) = P ( let )
take log both sides
log10^(x/2 + 1) = logP
(x/2 + 1) = P
put x = log64 from eqn (1)
( log64 )/2 + 1 = logP
log(64)½ +1 = logP
log8 + log10 = logP
logP = log8 × 10 = log80
P = 80
hence, 10^(x/2 +1) = 80 ( answer )
2nd method ///
=================
10^x = 64
take square root both sides
(10^x)½ = (64)½
10^x/2 = 8
multiply both sides with 10
10.10^x/2 = 8× 10
10^(x/2 + 1) =80
Ayush979Ay:
Thanks
Answered by
6
10^x = 64.
Now (10^x)^1/2+ 1
= (64)^1/2 x 10^1
= 8 x 10
= 80
^ means power
#HopeItHelps
@EklavyaKamal....
Now (10^x)^1/2+ 1
= (64)^1/2 x 10^1
= 8 x 10
= 80
^ means power
#HopeItHelps
@EklavyaKamal....
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