Question

10 resistances of 12 ohm each are connected in parallel what is the effective resistance?​

Answer 1

• R1=R2=R3=R4=R5=R6=R7=R8=R9=R10=12ohm

All are connected in parallel

$\boxed{\sf \dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\dots}$

$\\ \sf\longmapsto \dfrac{1}{R_{eq}}=\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}$

$\\ \sf\longmapsto \dfrac{1}{R_{eq}}=\dfrac{1+1+1+1+1+1+1+1+1+1}{12}$

$\\ \sf\longmapsto\dfrac{1}{R_{eq}}=\dfrac{10}{12}$

$\\ \sf\longmapsto R_{eq}=\dfrac{12}{10}$

$\\ \sf\longmapsto R_{eq}=1.2\Omega$

Answer 2

Answer:

1.2 ohm

Explanation:

In parallel combination

1/R = 1/12+1/12+1/12+1/12+1/12+1/12+1/12+1/12+1/12+1/12

1/R = 10/12

so

R = 1.2 ohm