10 resistors 1 ohm each are joined in series and then in parallel. what will be the ratio of effective resistance of the first to that of the second?
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Answered by
5
Answer:
Step-by-step explanation:
Answer:
When they are joined in series, the effective resistance is just their sum. Eff. Resistance(R) = 1 + 1 + upto 10 terms= 10
When they are joined in parallel, let the effective resistance be R, so: 1/R₁ = 10 →
R₁ = 1/10
1/R₁ = 1/1 + 1/1 + upto 10 terms
Hence, ratio of eff. resistance of 1st to that
of 2nd is:
R/R₁
(10)/(1/10)
⇒ 100: 1
Answered by
52
Answer:
refer to the attachment
hope it will help you xD
what's your pint I'd?
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