Question

10. Rohit borrowed Rs 60000 from a bank at 9% per annum for 2 years. He lent this sum of more
to Rohan at 10% per annum for 2 years. How much did Rohit earn from this transaction?
months. How much did she pay?
annum and Rs 1000 at 5% per annum. He clear​

Answer 1

Answer:

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Answer 2

Given : Principal amount P = Rs.60000,Time period T = 2 years,

Rate of interest R = 10% p.a.

⠀⠀⠀______________________________________________

We know that Simple Interest = (P × T × R)/100

on Substituting these values in above equation we get,

$:\implies\sf{SI = (60000 × 2 × 10)/100}$

$:\implies{\boxed{\frak{\purple{=Rs.12000}}}}$

• Principal amount P = Rs.60000
• Time period T = 2 years
• Rate of interest R = 9% p.a.

We know that Simple interest = (P × T × R)/100

on substituting these values in above equation We get,

$:\implies\sf{SI = (60000 × 2 × 9)/100}$

$\ \ :\implies{\boxed{\frak{\purple{=Rs.10800}}}}$

Amount gained by Rohit = Rs.12000 - Rs.10800

${\boxed{\frak{\purple{= Rs.1200}}}}$