Math, asked by upendra3254, 1 year ago

10 से 100 के बीच की एक संख्या अपने अंको के योग की 7 गुनी है यदि संख्या से 27 घटा दिया जाए तो उस संख्या के दोनों पलट जाते हैं वह मूल्य संख्या क्या है

Answers

Answered by Mankuthemonkey01
5
Hey mate!!!

Sankhya Ko 10x +y Maan lete hain
Koi bhi sankhya isi roop me Hoti hai isliye hmne 10x + y mana hai.

Diya hai anko ka Jod ka 7 Guna = sankhya
= 7(x + y) = 10x + y
aur
10x + y - 27 = 10y + x (kyoki diya hai sankhya palat jaati hai)
atah
=
10x + y - 27 = 10y + x \\  = 10x + y - 10y - x = 27 \\ 9x - 9y = 27 \\ 9(x - y) = 27 \\ x - y = 27 \div 9 \\ x - y = 3
ab
7(x + y) = 10x + y
=
7x + 7y = 10x + y \\ 10x + y = 7x + 7y \\ 10x  - 7x = 7y - y \\ 3x = 6y \\ x =  \frac{6y}{3}  \\ x = 2y
ab diya hai x = 2y
aur upar kiye yog se pata chala
x - y = 3
aur x = 2y
isliye
2y - y = 3
y = 3

ab hme y ka mulya pata hai.
x = 2y
x = 2 × 3
x = 6.
Aur sankhya hai
10x + y
= 10 × 6 + 3
= 60 + 3
= 63.

63 aapka Uttar hai.

Aasha hai yah Uttar aapki madad karega.
Dhanywad.

upendra3254: thanks
Mankuthemonkey01: welcome
upendra3254: ok
upendra3254: बाकी को हल करो
Mankuthemonkey01: kaun baaki
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