*10 सेमी बाजूच्या समभुज चौकोनाचा एक कर्ण 16 सेमी असल्यास चौकोनाचे क्षेत्रफळ किती?*
1️⃣ 80 चौसेमी
2️⃣ 128 चौसेमी
3️⃣ 48 चौसेमी
4️⃣ 96 चौसेमी
Answers
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Given :-
- Side of rhombus = 10 cm.
- Diagonal of rhombus = 16 cm.
To Find :-
- Area of rhombus = ?
Answer :-
As we know that,
- Diagonals of a rhombus bisect each other at 90° .
Let us assume that , diagonal of other diagonal is 2x cm .
So,
→ (D1/2)² + (D2/2)² = (side)²
→ (2x/2)² + (16/2)² = 10²
→ x² + 8² = 100
→ x = √(100 - 64)
→ x = 6 cm .
then,
→ Diagonal of other diagonal = 2x = 2 * 6 = 12 cm.
therefore,
→ Area of rhombus = (1/2) * D1 * D2 = (1/2) * 16 * 12 = 96 cm². (Ans.)
Learn more :-
ABCD is a rhombus with A = 60° , BC = (3x+5)cm , CD =(6x-10)cm and AC =(3y-1)cm. Find
x and y.
please urgent please
n...
brainly.in/question/25624939
3.
In the fig, AB || CD,FIND x.(Hint:Prove that AOB-COD).
brainly.in/question/17942233
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